Section1.4Absolute Value Equations and Inequalities (EQ4)
Objectives
Solve linear equations involving an absolute value. Solve linear inequalities involving absolute values and express the answers graphically and using interval notation.
An absolute value, written \(\lvert x \rvert\text{,}\) is the non-negative value of \(x\text{.}\) If \(x\) is a positive number, then \(\lvert x \rvert=x\text{.}\) If \(x\) is a negative number, then \(\lvert x \rvert=-x\text{.}\)
Which values are solutions to the absolute value equation \(3\lvert x-7 \rvert +5= 11\text{?}\) It may be helpful to rewrite the equation to isolate the absolute value.
Absolute value represents the distance a value is from 0 on the number line. So, \(\lvert x-7 \rvert = 2\) means that the expression \(x-7\) is \(2\) units away from \(0\text{.}\)
When solving an absolute value equation, begin by isolating the absolute value expression. Then rewrite the equation into two linear equations and solve. If \(c \gt 0\text{,}\)
\begin{equation*}
\lvert ax+b \rvert = c
\end{equation*}
Since the absolute value represents a distance, it is always a positive number. Whenever you encounter an isolated absolute value equation equal to a negative value, there will be no solution.
Draw the solution to \(\lvert x-7 \rvert \le 2\) on the number line.
A numberline from \(-9\) to \(9\text{.}\) The line is shaded between \(7\) and \(9\text{.}\)\(7\) is marked with a \([\) and \(9\) is marked with a \(]\text{.}\)
A numberline from \(-9\) to \(9\text{.}\) The line is shaded between \(5\) and \(9\text{.}\)\(5\) is marked with a \([\) and \(9\) is marked with a \(]\text{.}\)
A numberline from \(-9\) to \(9\text{.}\) The line is shaded between \(5\) and \(7\text{.}\)\(5\) is marked with a \([\) and \(7\) is marked with a \(]\text{.}\)
A numberline from \(-9\) to \(9\text{.}\) The line is shaded between \(2\) and \(7\text{.}\)\(2\) is marked with a \([\) and \(7\) is marked with a \(]\text{.}\)
A numberline from \(-9\) to \(9\text{.}\) The line is shaded from the left until \(7\text{,}\) and then onwards to the right from \(9\text{.}\)\(7\) is marked with a \(]\) and \(9\) is marked with a \([\text{.}\)
A numberline from \(-9\) to \(9\text{.}\) The line is shaded from the left until \(5\text{,}\) and then onwards to the right from \(9\text{.}\)\(5\) is marked with a \(]\) and \(9\) is marked with a \([\text{.}\)
A numberline from \(-9\) to \(9\text{.}\) The line is shaded from the left until \(5\text{,}\) and then onwards to the right from \(7\text{.}\)\(5\) is marked with a \(]\) and \(7\) is marked with a \([\text{.}\)
A numberline from \(-9\) to \(9\text{.}\) The line is shaded from the left until \(2\text{,}\) and then onwards to the right from \(7\text{.}\)\(2\) is marked with a \(]\) and \(7\) is marked with a \([\text{.}\)
When solving an absolute value inequality, rewrite it as compound inequalities. Assume \(k\) is positive. \(\lvert x \rvert \lt k \text{ becomes } -k \lt x \lt k\text{.}\)\(\lvert x \rvert \gt k \text{ becomes } x\gt k \text{ or } x\lt-k\text{.}\)
\(-\dfrac{14}{3} \lt x \lt 2\text{,}\)\(\left( -\dfrac{14}{3}, 2 \right)\)
A numberline from \(-9\) to \(9\text{.}\) The line is shaded between \(-\frac{14}{3}\) and \(2\text{.}\)\(-\frac{14}{3}\) is marked with a \((\) and \(2\) is marked with a \()\text{.}\)
A numberline from \(-9\) to \(9\text{.}\) The line is shaded from the left until \(5\text{,}\) and then onwards to the right from \(9\text{.}\)\(5\) is marked with a \()\) and \(9\) is marked with a \((\text{.}\)